Reference: GS paper 2005
Q 108
Q 108
Sudharkar Tripathi writes
Q108 YES IN 4TH ATTEMPTSO ANS IS (A)INITIAL--10H.0TFIRST ATTEMPT-6H4TSECOND-2H8T(BY REVESING 3H TO T AND 1H TO T)THIRD ATTEMPT-6T4HFOURTH-10T
The Answer should be a, 4 attempts minimum
And not d, Not possible.
The following explanation may confirm that answer is a, 4 attempts.
Q 108
It seems that in 4 attempt it is possible to get all 10 sides of T upside.
The sequence can be as follows:
10H at Start
First Attempt
6 H 4T
Second Attempt
8H 2T
Here
3T change over to 3H making 6H + 3T= 9H and leaving 1T
1H changes to 1T giving 2T and leaving 8H
Third Attempt4H 6T
Here
4H changes to 4T
Fourth attempt
10T
My sequence is different from the sequence as suggested by Sudharkar Tripathi. But it shows that minimum 4 attempts can be used to get 10T. Therefore, Tripathi is right and answer is a, 4 attempts.
Any Comment or Counter view.
Any one.
The Back Reference:
The question appears HERE
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